Two-Way Conveyor (Human load/ Robot Unload)

Hey everyone, here’s my attempt at a two-way conveyor concept. I needed a simple approach for my project without having to use python, because I don’t know programming, yet…

Feel free to use it , if it does the trick for ya

TWO WAY CONVEYOR TEST2.vcmx (8.8 MB)

Make sure the below encircled Times are matching for a seam-less flow

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Hi, is there a reason why you’re using the Interpolating transport instead of just switching the conveyor direction?


TWO WAY CONVEYOR TEST_v3.vcmx (9.0 MB)

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My plan is to have one fixture that moves back and forth. Human loads part on fixture, robot unloads the part, fixture goes back to loading starting point and repeat.

My solution was is by creating and sinking “interpolation” the fixture between the loading and loading nodes.

I would appreciate any better solution, that doesn’t require programming…

This is the process flow I need

The solution I sent with the direction change should work. That way you need a process less, and the fixture doesn’t need to be deleted and created again each time:
TWO WAY CONVEYOR TEST_v4.vcmx (8.9 MB)

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Thank you so much for the simpler solution :blush:

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I added a track process node to stop the fixture in the middle of the conveyor for 5 sec before going to robot.

On the way back to human, the fixture stops again at that track process node.

How can I prevent the fixture from stopping on the way back to human, but only stop when it’s going to robot?

One way of doing it would be to use the “Process Point” found in Conveyor Utilities.


You can select as “ProcessTimeType” a Property. It needs to be a real “Component Property” that you can create in your fixture, in the Product Type Editor. Then in your Processes, you can set it to 5s or 0s with an assign statement.

An easier method would be to use a standard Process Node, with a TransportIn+Delay+TransportOut for the way to the robot followed by a TransportIn+TransportOut for the way back. (don’t forget to set the source and destinations on “ComponentContainer”)

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Thank you again Tilma. Very helpful solutions